How much heat is evolved in converting 1.00 mol of steam at 160.0 ∘C to ice at -50.0 ∘C?

Roger the Mole

(36.03 J/(mol·°C)) x (1.00 mol) x (160.0 - 100.0)°C = 2161.8 J from cooling the steam to its boiling point (40660 J/mol) x (1.00 mol) = 40660 J from condensing the steam (75.37 J/(mol·°C)) x (1.00 mol) x (100.0 - 0)°C = 7537 J from cooling the condensed steam to its freezing point (6010. J/mol) x (1.00 mol) = 6010. J from making ice (37.60 J/(mol·°C)) x (1.00 mol) x (0 - (-50.0))°C = 1880 J from cooling the ice to -50.0°C 2161.8 J + 40660 J + 7537 J + 6010. J + 1880 J = 58248.8 J = 58.2 kJ total