Capacitor 30.0 𝜇F & resistor 70.0 Ω connected in series to battery 5.00 V. What is charge 𝑄 on capacitor 0.00100s after connection made?

billrussell42

voltage on a cap, charging v = v₀[1–e^(–t/τ)] v₀ is the battery voltage v is the voltage after time t R is resistance in ohms, C is capacitance in farads t is time in seconds RC = τ = time constant 0.00100s = 1 ms τ = RC = 70•30µ = 2100µ = 2.1 ms v = v₀[1–e^(–t/τ)] v = 5[1–e^(–1m/2.1m)] v = 5[1–e^(–0.476)] v = 5[1–0.6211452] v = 1.894 volts Q = CV = 30µ• 1.894 = 56.8 µC