# Joshalyn caught, tagged and released 135 trout into a lake. The next day she caught 48 trout, of which 10 were tagged. Using this ratio,?

Dan

What kind of a name is Joshalyn?

Michael

Set up a ratio with total on the top and tagged on the bottom x/135 = 48/10 Multiply both sides by 135 x = 48/10 * 135 x = 648 <––––––

JOE

Michael might have it, but I don't think you can have a complete answer if you don't have an approximate number of total trout in the lake can you?

Anonymous

648 fish dude. 20x7divided by 14 x 11x4divided by 7=648

Anonymous

She was then arrested for illegally stocking a lake! and the fish were removed and disposed of!

zipper

NOT Enough information to figure this out. Is Joshalyn the only one tagging fish. There is no ratio here just a flat 135 trout have been tagged as far as we know! Not hard to figure out at all!

Stella

10/48 is 0.208 This means that 20.8% of the fish she caught on the second day were tagged. Assuming the same percentage for the total lake population she needs to find the number that 135 is 20.8 % of. So, 135/.208 is 649.